Hello Kav. I absolutely love your breakdown on this. Bravo my friend! I am referring to European Roulette. I have recently found out there are a few casinos in Las Vegas that have European Roulette tables. You are correct Kav with your explanation.

If we bet One Dozen, the House bets us 2 to 1 that 25 numbers will beat 12. So the actual 2 to 1 on One Dozen is actually 2.08 to 1 because if we divide the House's 25 numbers to our 12, it equals 2.08 instead of two. So if we divide 2 into 2.08 that equals 96% which is a difference of the 4% . I like the mathematical breakdown that was demonstrated in your answer Kav. Then if we back 2 dozen, the House makes *US* lay 2 to 1 that 24 numbers will beat 13 so the proper odds are 1.84 to 1 and we have a disadvantage of 8 %.

If we bet 1 unit on 35 numbers, we could lose 35 units if one or two numbers came out and the most we could win for that coup is 1 unit. We were therefore laying down 35 to 1 when the real odds are 35 to 2, or 17.5 to 1. So we were laying double the proper odds, or in other words giving the House a 100% advantage over us.

Well done Kav!