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### Author Topic: "Couple"  (Read 12370 times)

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#### Maes

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• Posts: 21
##### "Couple"
« on: June 02, 2015, 08:23:13 PM »
What are the odds that a dozen to occur to times?

Mathematical the odd is almost 1/(3^2)  , 1 in 9 tries .
This in procentual is 11,11% .
Pretty high I say.

"couple" consist in a progression like this :
(1,3) , (1,3) ,(1,3) ,(1,3) , (1,3), (1,3), (1,3)

this 7 couples we will bet like this :

1.Pick a random(or how you like) dozen/etc.
2.Put 1 unit .
a. If we lose go to the next couple (1,3)
b. If we win put 3 unit on the same dozen/etc.
3.Repet 7 times
If we lose this 7 couples , we have the next couples :
(2,1) , (3,1) , (3,2) , (4,2) ,( 4,3 ) ,(5,4)....( how much you bankroll can support, i will explain in the comment if you dont understand how I make this couples)

Steps for this :
1.Pick a random dozen.
2.Put  2 units ( the first number)  if we lose go to the next couple
3.If we win
- bet on the same dozen with the second number as units
Now if we win the second bet we have like (0,1,2) units profit .
if we lose we have like 1 unit profit , and we stay a the same couple .

The sesion is over when you win both the bets.

Example for the second phase :

Let's say we bet on the first dozen (1-12) and we are at the the couple (4,3) .
We lost 19 units  .
If the first bet wins , we have 4*3=12 unit
If the second bet lose , we have 12-4 - 3 =  5 units .

Now we pick another dozen , and repet the couple (4,3) .

This is "couple" , by Maes. Sorry for the bad English (.

EDIT 1 : Because of my math second couples are :
(3,1) , (3,2) ,(4,3),(5,4) , (7,5),(9,5) ...

« Last Edit: June 02, 2015, 10:39:28 PM by Maes »

#### Reyth

##### Re: "Couple"
« Reply #1 on: June 03, 2015, 06:27:45 AM »
Very interesting way to do a progression.  Have you ever tried to take the progression and string it out to see what it looks like?  Makes me wonder if you must win before you hit table limits...

#### Maes

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• Posts: 21
##### Re: "Couple"
« Reply #2 on: June 03, 2015, 10:51:00 AM »
What table limits are we looking for ? I found like 60 units , and even 400 .
for 60 units we have like 19-20 steps .
I did tried to make a program in c++ , still working on it .

But this progresion i think is very flexible because :

1. If we win the first bet , we can go on step back , or continue with the second one .
2. On the second bet , you can put another random dozen ( if you like )

Why i think this works?

The change that the same dozen occurs again (from betting , RND , observing) is pretty high . The only problem that I have is that you have like  1/3 to guess it (when iwill begin).

I am hopping that somebody could help , to find where you could bet and be in maximum profit.

#### dobbelsteen

##### Re: "Couple"
« Reply #3 on: June 03, 2015, 11:45:45 AM »
I have no idia what a couple is. Please be more clearly.

#### Maes

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• Posts: 21
##### Re: "Couple"
« Reply #4 on: June 03, 2015, 11:59:13 AM »
couple is the pair (x,y)  Ex: (1,3) is a couple , I prefer to name this pair a couple because there are 2 numbers

#### Reyth

##### Re: "Couple"
« Reply #5 on: June 04, 2015, 04:01:24 AM »
Ya apparently he is making a progression tree by using the couple format.  He appears to start with 7 couples:

(1,3) (1,3) (1,3) (1,3) (1,3) (1,3) (1,3)

So he is betting twice on a single dozen.  First 1 unit then 3 (the first couple).  Then he moves to the second couple (1,3) again. So for the first two couples the progression looks like:

1313

THEN he starts a second tree like:

(3,2) (3,2) (3,2) (3,2) (3,2) (3,2) (3,2)

So that after these two trees the full progression would look like:

1 3 1 3 1 3 1 3 1 3 1 3 1 3 3 2 3 2 3 2 3 2 3 2 3 2 3 2

I dunno, I thought the idea was charming and like could be configured with "killer couples" that would force wins while cleverly remaining below table limits?  I mean maybe even an algorithm could be created to make couples based on overall loss or loss streaks?
« Last Edit: June 04, 2015, 04:10:42 AM by Reyth »

#### Maes

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• Posts: 21
##### Re: "Couple"
« Reply #6 on: June 04, 2015, 06:08:58 AM »
after the 7 couples , you you have (3,1) , (3,2) ,(4,3) , you repet these only if you hit the first bet , if not move to the next couple

so if i put 3 on a dozen , and i hit , i go with 1 on the same dozen ,
if i lose , move next to the (3,2) if i lose the 3 , go to the (4,3) , in my test so far ( fun mode) , i manage all the time to double my bankroll (maybe luck) and got to the 16 couple in the series , this means like in 30 spins i hit 6 dozen , and the last 2 was in a row .
« Last Edit: June 04, 2015, 10:36:08 AM by Maes »

#### Reyth

##### Re: "Couple"
« Reply #7 on: June 04, 2015, 08:07:52 AM »
Ok well this sounds very interesting.

Ok so you start with 7 couples (1,3) and then you move to the secondary couple system:

(3,1) , (3,2) ,(4,3),(5,4) , (7,5),(9,5)

What does the 16th couple look like?
« Last Edit: June 04, 2015, 08:16:13 AM by Reyth »

#### Maes

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• Posts: 21
##### Re: "Couple"
« Reply #8 on: June 04, 2015, 10:20:56 AM »
1-7:7x(1,3)  loss: -1->-7          win(profit): +8->+2
8: (3,1)                 -10                                  +2
9: (3,2)                 -13                                    0
10: (4,3)               -17                                   +1
11:(5,4)                -22                                   +1
12:(7,5)                -29                                   +2
13:(9,6)                -38                                   +1
14:(10,9)              -48                                   0
15:(13,12)            -61                                   +2
16:(16,15)            -77                                   +1
17:(20,19)            -97                                   +1
18:... you can do the math from here

if you repeat the couple (4,3) two times ,first  you have  profit because 4*3-4=8 ,now you put 3 next , if you lose you have 8-3 =5 (this will be aditional profit ) ,
nest you are again at (4,3) you win both bets you get +1 .
Total profit  5+1 =6 units .

Hope you like ,
I can do a "couple progresion" to EC if anybody is interesting

« Last Edit: June 04, 2015, 10:32:27 AM by Maes »

#### Reyth

##### Re: "Couple"
« Reply #9 on: June 04, 2015, 11:51:06 AM »
Wow this system looks amazing.  Do you think it would ever get up to 400 units on the bet before winning?

Wow I'm playing it now!  The awesome powa of teh parlay!  Its like INSTA-COUP!

Ok finally reached the secondary couples area & down 7 units...  Wow.  Made it to the 10th couple and didn't even have to make the second bet & was up 2 units.

Let me enter this into the comp and find out the max loss on a single dozen...

The number 41 appears to be it.  I can generate a loss distribution on this...

« Last Edit: June 04, 2015, 12:30:22 PM by Reyth »

#### Maes

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• Posts: 21
##### Re: "Couple"
« Reply #10 on: June 04, 2015, 12:07:25 PM »
Now let's rob some casinos

Ps: If this system works , I kindly accept donations
« Last Edit: June 04, 2015, 12:11:13 PM by Maes »

#### Reyth

##### Re: "Couple"
« Reply #11 on: June 04, 2015, 12:33:18 PM »
How do we make a progression out to 41 couples?  I have a table betting limit of 400 units.  We should find out how far we can go to see what the odds are of losing.  If we can make it to 41 couples, we can expect not to lose...

Errrf, except we need more than a single hit to win... >.<

One technique is couple stepping, where if you do hit, you can move back in the couple list which will give you more progression steps to your next hit.

Let me see if I can improve the results with random placement of a dozen....

Ok, if we let random.org choose our dozen after every hit, we only need 36 max(5 improvement though random placement).

Maybe we can start over after 1 hit?
« Last Edit: June 04, 2015, 01:05:56 PM by Reyth »

#### Maes

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• Posts: 21
##### Re: "Couple"
« Reply #12 on: June 04, 2015, 12:45:23 PM »
for the next couple you do this :

let's take -97 loss

97/2=48

next 48/2=24

so x is 25 , and y 24

i hope you get the "formula" behind

#### Reyth

##### Re: "Couple"
« Reply #13 on: June 04, 2015, 01:02:26 PM »
Ok, what about these 0 profit steps?  Can they be used to increase our progress?

Also, you said something about repeating a step and not moving forward?  When can we do that?  ===> OK I get this, you would have to win first and you would gain an extra couple of steps by repeating.

But how do I make a 0 profit step?  Maybe we can put in a ton of those and reach 36 couples?

And then we can probably do a Dobble trigger and gain a few more steps...
« Last Edit: June 04, 2015, 01:09:48 PM by Reyth »

#### Reyth

##### Re: "Couple"
« Reply #14 on: June 04, 2015, 01:27:34 PM »
1-7:7x(1,3)  loss: -1->-7          win(profit): +8->+2
8: (3,1)                 -10                                  +2
9: (3,2)                 -13                                    0
10: (4,3)               -17                                   +1
11:(5,4)                -22                                   +1
12:(7,5)                -29                                   +2
13:(9,6)                -38                                   +1
14:(10,9)              -48                                   0
15:(13,12)            -61                                   +2
16:(16,15)            -77                                   +1
17:(20,19)            -97                                   ??
18:(25,24)            -122
19:(31,30)            -153
20:(39,38)            -192
21:(48,49)            -240
22:(60,61)            -300
23:(75,76)            -375
24:(94,95)            -469
25:(118,119)        -587
26:(147,148)        -734
27:(184,185)        -918
28:(230,231)        -1148
29:(287,288)        -1435
30:(359,360)        -1794
====================================
TABLE LIMITS
====================================
31:(449,450)

I don't know if my figures are correct...

But let's talk about a 30 bet loss and below:

(30)19 0.00000542265299016502  1 in 184502

(31)13 0.000003710236256428698  1 in 269543 chances of failure to hit
(32)4   0.000001141611155824215
(33)3   0.000000856208366868161
(34)7   0.000001997819522692376
(35)2   0.0000005708055779121074
(36)1   0.0000002854027889560537

3503820 total results.

1 in 269543 sounds super awesome actually.  Better than anything I have been able to accomplish so far.

Can we start over though after only 1 win?
« Last Edit: June 04, 2015, 01:44:00 PM by Reyth »