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Royal Panda roulette

Author Topic: Red black chops  (Read 473 times)

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Ripple

Red black chops
« on: January 30, 2019, 12:33:10 AM »
What is the longest streak of rbrbrbrbrbrbr that you have seen?

 

Third

Re: Red black chops
« Reply #1 on: January 30, 2019, 12:35:39 AM »
In computer simulation, 25.  I've seen Martingalers try to avoid the worst with FTL but that acronym actually stands for "Fail The Longest". XD
 

rimsky

Re: Red black chops
« Reply #2 on: January 30, 2019, 06:21:53 AM »
History recorded a sequence of 32 intermittence rbrbrbrb... in a land based casino in Europe (I can't remember where exactly).

However, looking at every permanence (number sequence) around, you can easily see that this specific event is less frequent than red or black streaks. Once I played a long martingale against intermittence rbrbrbrb... starting with 0.10€ chip and never lose the game in a couple of months. I gave up because eventually I faced twice in a row a 250€ bet which I luckily won, but I could have lost. And probably next time I would have lost so I dismiss the play. But even if later I looked at other strategies and play, I'm still sure that devising a smart good strategy against rbrbrb... intermittence can be profitable.
« Last Edit: January 30, 2019, 06:23:47 AM by rimsky »
 
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Dane

Re: Red black chops
« Reply #3 on: January 30, 2019, 07:43:31 AM »
Many years ago an intermittence idea struck me. I had tried to catch a repeat of a single number WITHIN a red OR black series. It goes without saying that the number of wagered single numbers, as long as no such repeat came in the continued series, must be one, two, three, four, five........
Then it struck me: A similar procedure within an intermittence series must involve one, one, two, two,
three, three, four, four, five, five wagered single numbers. Use it as you like.