Recently BlueAngel pointed out that a method of mine is too complicated. He may be right.

Here is a more simple suggestion. The "?", however, means that you ought to count to

two, three...in order to find the best. Test it yourself and find the best. Take it or leave it.

Once again you need a pen and a piece of paper with at least 12x3 spaces. Reserved for 1-36 at the

table. Simply write the coming numbers where they belong in accordance with the table layout.

Some patterns occur in the three columns (1-34, 2-35 and 3-36) on the small piece of paper.

Fields filled in may stand alone or side by side. Two, three, four or more? As you´ll continue the experiment, more adjacent fields or spaces filled in must come.

Now the question is, if we ought go go for exactly two, exactly three, exactly four or more.

If you find that counting to THREE is the optimal solution, then here is an example:

#3 and #6 have appeared, but not #9 or #12. Then you should start betting #6 (I myself prefer flat betting). You may get a hit and then leave this number. Or #12 comes. In that case you should leave the number too. 3-6-9-12 are not exactly THREE, you see.

"THERE´LL BE TIME ENOUGHT FOR COUNTING, WHEN THE DEAL IS DONE", as Kenny Rigers is singing in "The Gambler". I myself don´t like counting too much. The suggested procedure does not involve counting money, chips, spins , minutes or hours. Just fill in spaces and count to ?

"ONE, TWO, THREE, FOUR, FIVE, SIX, SEVEN. ALL GOOD CHILDREN TO TO HEAVEN"

(The Beatles).

EXACTLY SEVEN EMPTY SPACES END THE GAME. Exactly seven Straight Up sleepers in the area: No more bets. The session has ended.

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